document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715540>Question 715540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> contract the expressions. that is, use the properties of logarithms to write each expression coefficient of 1.\r<BR>\n" );
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document.write( "Ln 3 - 2 ln(6+9)\r<BR>\n" );
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document.write( "how do i work out this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439469 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given: (1) ln(3) - 2*ln(6+9) or<BR>\n" );
document.write( "(2) ln(3) - 2*ln(15) or<BR>\n" );
document.write( "using 2*ln(x) = ln(x)^2 we get<BR>\n" );
document.write( "(3) ln(3) - ln(15)^2 or<BR>\n" );
document.write( "(4) ln(3) - ln(225) or<BR>\n" );
document.write( "using ln(a) - ln(b) = ln(a/b) we get<BR>\n" );
document.write( "(5) ln(3/225) or<BR>\n" );
document.write( "(6) ln(1/75) or<BR>\n" );
document.write( "(7) ln(1) - ln(75) or<BR>\n" );
document.write( "(8) 0 - ln(75) or<BR>\n" );
document.write( "(9) -ln(75)<BR>\n" );
document.write( "Answer: (1) evaluates to -ln(75) = -4.317...<BR>\n" );
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