document.write( "Question 715517: Find an equation in general form of the perpendicular bisector of the line segment with endpoints A(7,-1) and B(-4,2) \n" ); document.write( "

Algebra.Com's Answer #439462 by mananth(16946) $\"\"$ $\"About$

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A(7,-1) and B(-4,2)\r
\n" ); document.write( "\n" ); document.write( "mid point co-ordinates x=(7+(-4))/2=3/2
\n" ); document.write( "y=(-1+2)/2= =1/2\r
\n" ); document.write( "\n" ); document.write( "(3/2, 1/2)\r
\n" ); document.write( "\n" ); document.write( "A(7,-1) and B(-4,2)\r
\n" ); document.write( "\n" ); document.write( "slope = ((2-(-1))/(-4-7)\r
\n" ); document.write( "\n" ); document.write( "slope=- 3/11\r
\n" ); document.write( "\n" ); document.write( "the slope of line perpendicular to this line will have slope of 11/3\r
\n" ); document.write( "\n" ); document.write( "m=11/3 , point (3/2, 1/2)\r
\n" ); document.write( "\n" ); document.write( "y-(1/2) = 11/3( x-(3/2))\r
\n" ); document.write( "\n" ); document.write( "y-1/2 =11/3(2x-3)/2)\r
\n" ); document.write( "\n" ); document.write( "simplify\r
\n" ); document.write( "\n" ); document.write( "2*3(y-1/2) = 11(2x-3)\r
\n" ); document.write( "\n" ); document.write( "6y-3=22x-33\r
\n" ); document.write( "\n" ); document.write( "6y=22x-30\r
\n" ); document.write( "\n" ); document.write( "y=(11/3)x -5\r
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