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document.write( "a rectangular table top has a perimeter of 26 inches and an area of 40 square inches find the dimensions \n" );
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Algebra.Com's Answer #439437 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "26=2L+2W \n" ); document.write( "A=LW \n" ); document.write( "40=LW \n" ); document.write( "L=40/W \n" ); document.write( "26=2(40/W)+2W \n" ); document.write( "26=80/W+2W \n" ); document.write( "26=(80+2W*W)/W \n" ); document.write( "26=(80+2W^2)/W CROSS MULTIPLY. \n" ); document.write( "26W=80+2W^2 \n" ); document.write( "2W^2-26W+80=0 \n" ); document.write( "2(W^2-13W+40)=0 \n" ); document.write( "2(W-5)(W-8)=0 \n" ); document.write( "W-5=0 \n" ); document.write( "W=5 ANS. L=8 ANS. \n" ); document.write( "W-8=0 \n" ); document.write( "W=8 ANS. L=5 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "40=5*8 \n" ); document.write( "40=40 \n" ); document.write( "26=2*5+2*8 \n" ); document.write( "26=10+16 \n" ); document.write( "26=26 \n" ); document.write( " |