document.write( "Question 715443: \r
\n" ); document.write( "\n" ); document.write( "a rectangular table top has a perimeter of 26 inches and an area of 40 square inches find the dimensions
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Algebra.Com's Answer #439437 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
P=2L+2W
\n" ); document.write( "26=2L+2W
\n" ); document.write( "A=LW
\n" ); document.write( "40=LW
\n" ); document.write( "L=40/W
\n" ); document.write( "26=2(40/W)+2W
\n" ); document.write( "26=80/W+2W
\n" ); document.write( "26=(80+2W*W)/W
\n" ); document.write( "26=(80+2W^2)/W CROSS MULTIPLY.
\n" ); document.write( "26W=80+2W^2
\n" ); document.write( "2W^2-26W+80=0
\n" ); document.write( "2(W^2-13W+40)=0
\n" ); document.write( "2(W-5)(W-8)=0
\n" ); document.write( "W-5=0
\n" ); document.write( "W=5 ANS. L=8 ANS.
\n" ); document.write( "W-8=0
\n" ); document.write( "W=8 ANS. L=5 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "40=5*8
\n" ); document.write( "40=40
\n" ); document.write( "26=2*5+2*8
\n" ); document.write( "26=10+16
\n" ); document.write( "26=26
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