document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715413>Question 715413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Suppose that the length of one leg of a right triangle is 4 inches more than the length of the other leg. If the length of the hypotenuse is 20 inches, find the lengths of the two legs.\r<BR>\n" );
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document.write( "Can someone show me how to solve this problem and the answer? Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439421 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A^2+B^2=C^2<BR>\n" );
document.write( "X^2+(X+4)^2=20^2<BR>\n" );
document.write( "X^2+X^2+8X+16=400<BR>\n" );
document.write( "2X^2+8X+16-400=0<BR>\n" );
document.write( "2X^2+8X-384=0<BR>\n" );
document.write( "2(X^2+4X-192)=0<BR>\n" );
document.write( "(X+16)(X-12)=0<BR>\n" );
document.write( "X-12=0<BR>\n" );
document.write( "X=12 IN. ANS. FOR SIDE A.<BR>\n" );
document.write( "12+4=16 IN. ANS. FOR SIDE B.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12^2+16^2=20^2<BR>\n" );
document.write( "144+256=400<BR>\n" );
document.write( "400=400<BR>\n" );
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