document.write( "Question 715327: Flying against the wind, an airplane travels 1800 km in 3 hours. Flying with the wind, the same plane travels 5740 km in 7 hours. What is the rate of the plane in still air and what is the rate of the wind?
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Algebra.Com's Answer #439381 by stanbon(75887) $\"\"$ $\"About$

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Flying against the wind, an airplane travels 1800 km in 3 hours. Flying with the wind, the same plane travels 5740 km in 7 hours. What is the rate of the plane in still air and what is the rate of the wind?
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\n" ); document.write( "Against DATA:
\n" ); document.write( "distance = 1800 km ; time = 3 hrs ; rate = d/t = 1800/3 = 600 km/hr
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\n" ); document.write( "With DATA:
\n" ); document.write( "distance = 5740 km ; time = 7 hrs ; rate = d/t = 5740/7 = 820 km/hr
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\n" ); document.write( "Equation:
\n" ); document.write( "Against: p - w = 600
\n" ); document.write( "With:::: p + w = 820
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\n" ); document.write( "Add and solve for \"p\":
\n" ); document.write( "2p = 1420
\n" ); document.write( "p = 710 km/hr (speed of the plane in still air)
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\n" ); document.write( "Solve for \"w\":
\n" ); document.write( "Subtract one equation from the other and solve for \"w\":
\n" ); document.write( "2w = 120
\n" ); document.write( "w = 60 km/hr (speed of the wind)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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