document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715311>Question 715311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An athlete jogs at 6 miles per hour and at 9 miles per hour for a total time of 1 hour, covering a distance of 7 miles. How long does the athlete jog at each speed?\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439373 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An athlete jogs at 6 miles per hour and at 9 miles per hour for a total time of 1 hour, covering a distance of 7 miles. How long does the athlete jog at each speed?<BR>\n" );
document.write( "d = r*t<BR>\n" );
document.write( "t = d/r<BR>\n" );
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document.write( "d = distance at 6 mi/hr<BR>\n" );
document.write( "d/6 + (7-d)/9 = 1<BR>\n" );
document.write( "9d + 6(7-d) = 54<BR>\n" );
document.write( "9d + 42 - 6d = 54<BR>\n" );
document.write( "3d = 12<BR>\n" );
document.write( "d = 4 miles at 6 mi/hr --> t = 2/3 hour<BR>\n" );
document.write( "--> 1/3 hour at 9 mi/hr<BR>\n" );
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