document.write( "Question 63117: How do you solve for x: 3/2x+4x-3(2/3x+1/3-2)=2(5-1/2+3/2)also how do you solve for x: 2x+6x-4(3/2x+5)=4x-1/2+6x-5/2 please help me!?! Idont understand what and how to start the equation and how to get the answer. \n" ); document.write( "
Algebra.Com's Answer #43935 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
(3/2)X+4X-3([2/3]X+1/3-2)=2(5-1/2+3/2)
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\n" ); document.write( "(3/2=1.5),(-3*2/3=-6/3=-2),(-3*1/3=-1),(-3*-2=6),(5-[1/5=.5].5+[3/2=1.5]1.5=6)
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\n" ); document.write( "HOPE THIS HELPS.
\n" ); document.write( "WHAT GRADE ARE YOU IN? DOESN'T THE TEACHER EXPLAIN HOW TO HANDLE ITEMS WITH () AND THE SEQUENCE OF OPERATIONS (POWERS, MULTIPLY/DIVIDE THEN ADD/SUBTRACT, LEFT TO RIGHT)??????????
\n" ); document.write( "IF YOU AREN'T TAUGHT THE VERY BASICS YOU'LL NEVER BE ABLE TO LEARN HOW TO DO ALGEBRA.
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\n" ); document.write( "1.5X+4X-2X-1+6=2(6)
\n" ); document.write( "3.5X+5=12
\n" ); document.write( "3.5X=7
\n" ); document.write( "X=7/3.5
\n" ); document.write( "X=2 PROOF
\n" ); document.write( "PROOF
\n" ); document.write( "1.5*2+4*2-3([2/3]2+1/3-2)=12
\n" ); document.write( "3+8-3*2-2*2+3*1/3-2*-3=12
\n" ); document.write( "3+8-4-1+6=12
\n" ); document.write( "11-5+6=12
\n" ); document.write( "12=12\r
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