document.write( "Question 714369: Hello, i need some guidance on this hyperbola problem. On my test, it says to find the vertices, center and the foci of y^2 over 5, minus x^2 over 11=1. Or, if this is another way to write out my problem-> y^2/5-x^2/11=1. Thank you \n" ); document.write( "
Algebra.Com's Answer #439320 by lwsshak3(11628)\"\" \"About 
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find the vertices, center and the foci of y^2 over 5, minus x^2 over 11=1.
\n" ); document.write( "y^2/5-x^2/11=1
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis:
\n" ); document.write( "Its standard form: \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\", (h,k)=)x,y) coordinates of center.
\n" ); document.write( "..
\n" ); document.write( "For given equation:
\n" ); document.write( "center:(0,0)
\n" ); document.write( "..
\n" ); document.write( "a^2=5
\n" ); document.write( "a=√5
\n" ); document.write( "vertices: (0,0±a)=(0,0±√5)=(0,-√5), (0,+√5)
\n" ); document.write( "..
\n" ); document.write( "b^2=11
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2+b^2=5+11=16
\n" ); document.write( "c=√16=4
\n" ); document.write( "Foci: (0,0±c)=(0,0±4)=(0,-4), (0,+4)
\n" ); document.write( " \n" ); document.write( "
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