document.write( "Question 715197: Suppose that john invested a certain amount of money at 3% interest, and he invested $750 more than that amount at 5%. His total yearly interest was $157.50. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #439312 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Amount @ 3.00% x \n" ); document.write( "Amount @ 5.00% 1 x + 750 \n" ); document.write( "Total interest earned = 157.50 \n" ); document.write( " \n" ); document.write( "3.00% x+ 5.00% ( 1 x + 750 )= 157.5 \n" ); document.write( "3.00% x+ 5.00% * 1 x + 37.5 = 157.5 \n" ); document.write( "3.00% x+ 5.00% x + 37.5 = 157.5 \n" ); document.write( "0.03 x+ 0.05 x = 120 \n" ); document.write( "0.08 x = 120 \n" ); document.write( " x= 1500 Amount @ 3.00% \n" ); document.write( " = \n" ); document.write( "Amount @ 5.00% = 1 * 1500 + 750 \n" ); document.write( " = 2250 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "CHECK Total interest \n" ); document.write( "45 + 112.5 = 157.5 \n" ); document.write( " \n" ); document.write( " |