document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63027>Question 63027</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> please help!!\r<BR>\n" );
document.write( "\n" );
document.write( "-2^0(m^0 - 2) - 3(m - 3)= -2(m + 3^0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43931 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Anything to the 0 power is 1.<BR>\n" );
document.write( "-2^0(m^0 - 2) - 3(m - 3)= -2(m + 3^0)<BR>\n" );
document.write( "-1(1-2)-3(m-3)=-2(m+1)<BR>\n" );
document.write( "-1(-1)-3(m)-3(-3)=-2(m)-2(1)<BR>\n" );
document.write( "1-3m+9=-2m-2<BR>\n" );
document.write( "10-3m=-2m-2<BR>\n" );
document.write( "-10+10-3m=-2m-2-10<BR>\n" );
document.write( "-3m=-2m-12<BR>\n" );
document.write( "-3m+2m=2m-2m-12<BR>\n" );
document.write( "-m=-12<BR>\n" );
document.write( "-m/-1=-12/-1<BR>\n" );
document.write( "m=12<BR>\n" );
document.write( "Happy Calculating!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );