document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715224>Question 715224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ABCD is a rectangle. The area of the rectangle is 40 square feet.<BR>\n" );
document.write( "The length is 3 more than the width.\r<BR>\n" );
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document.write( "A) Find the measure of each length and each width<BR>\n" );
document.write( "B) Find the length of the diagonal, rounded to the nearest tenth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439300 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of rectangle = l*w\r<BR>\n" );
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document.write( "Width be x<BR>\n" );
document.write( "Length = x+3\r<BR>\n" );
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document.write( "x(x+3) =40\r<BR>\n" );
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document.write( "x^2+3x=40<BR>\n" );
document.write( "x^2+3x-40=0\r<BR>\n" );
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document.write( "x^2+8x-5x-40=0\r<BR>\n" );
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document.write( "x(x+8)-5(x+8)=0\r<BR>\n" );
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document.write( "(x+8)(x-5)=0\r<BR>\n" );
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document.write( "Therefore x= -8 OR x=5\r<BR>\n" );
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document.write( "Ignore negative\r<BR>\n" );
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document.write( "x=5 is the width\r<BR>\n" );
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document.write( "width = 5 feet\r<BR>\n" );
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document.write( "Length = x+3----> 8feet </SPAN>\n" );
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