document.write( "Question 714990: 17 From the top of a vertical cliff 68 m high, an observer
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document.write( "notices a yacht at sea. The angle of depression to the
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document.write( "yacht is 47è. The yacht sails directly away from the cliff,
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document.write( "and after 10 minutes the angle of depression is 15è. How
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document.write( "fast does the yacht sail? \n" );
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Algebra.Com's Answer #439253 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "T = top of the cliff (we assume eye of observer is there, 68 meters above water surface) \n" ); document.write( "B = bottom of the cliff (at water level) \n" ); document.write( "X = initial position of the yacht \n" ); document.write( "Y = position of the yacht 10 minutes later \n" ); document.write( "TH = a horizontal line, parallel to BY. \n" ); document.write( "angle HTX = \n" ); document.write( "angle HTY = \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The yacht covered \n" ); document.write( " \n" ); document.write( "We could say that its speed in meters per minute is |