document.write( "Question 715078: \r
\n" ); document.write( "\n" ); document.write( "John has dimes and quarters worth $6.50 he has two less quarters than dimes. how many of each type does he have?
\n" ); document.write( "

Algebra.Com's Answer #439235 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.10D+.25Q=6.50
\n" ); document.write( "D=Q+2
\n" ); document.write( ".10(Q+2)+.25Q=6.50
\n" ); document.write( ".10Q+.20+.25Q=6.50
\n" ); document.write( ".35Q=6.50-.20
\n" ); document.write( ".35Q=6.30
\n" ); document.write( "Q=6.30/.35
\n" ); document.write( "Q=18 QUARTERS.
\n" ); document.write( "D=18+2
\n" ); document.write( "D=20 DIMES.
\n" ); document.write( "PROOF:
\n" ); document.write( ".10*20+.25*18=6.50
\n" ); document.write( "2.00+4.50=6.50
\n" ); document.write( "6.50=6.50
\n" ); document.write( "
\n" );