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document.write( "John has dimes and quarters worth $6.50 he has two less quarters than dimes. how many of each type does he have? \n" );
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Algebra.Com's Answer #439235 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .10D+.25Q=6.50 \n" ); document.write( "D=Q+2 \n" ); document.write( ".10(Q+2)+.25Q=6.50 \n" ); document.write( ".10Q+.20+.25Q=6.50 \n" ); document.write( ".35Q=6.50-.20 \n" ); document.write( ".35Q=6.30 \n" ); document.write( "Q=6.30/.35 \n" ); document.write( "Q=18 QUARTERS. \n" ); document.write( "D=18+2 \n" ); document.write( "D=20 DIMES. \n" ); document.write( "PROOF: \n" ); document.write( ".10*20+.25*18=6.50 \n" ); document.write( "2.00+4.50=6.50 \n" ); document.write( "6.50=6.50 \n" ); document.write( " |