document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=715079>Question 715079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two complementary angles are in a ratio of 1 to 4.  find the measure of each angle. (what are complementary angles? what is there some?) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439234 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> COMPLEMENTARY ANGLES ADD UP TO 90 DEGREES.<BR>\n" );
document.write( "X+Y=90<BR>\n" );
document.write( "Y=90-X<BR>\n" );
document.write( "1/4=X/Y<BR>\n" );
document.write( "1/4=X/(90-X) CROSS MULTIPLY.<BR>\n" );
document.write( "4X=90-X<BR>\n" );
document.write( "4X+X=90<BR>\n" );
document.write( "5X=90<BR>\n" );
document.write( "X=90/5<BR>\n" );
document.write( "X=18 DEGREES FOR THE SMALLER ANGLE.<BR>\n" );
document.write( "18+Y=90<BR>\n" );
document.write( "Y=90-18<BR>\n" );
document.write( "Y=72 DEGREES FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "1/4=18/72<BR>\n" );
document.write( "72=72<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );