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document.write( "The sum of John and Kevin's age is 74. In three years, John will be three times as old as Kevin. How old are John and Kevin now?\r
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document.write( "A movie theater charges $ 10 for an adult ticket and 6 $ for a child's ticket. The screening of a new movie had attendance of 335 patrons ( adults and children) and generated revenue of $ 2 590. How many adults and how many children attended the movie screening? \n" );
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Algebra.Com's Answer #439174 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! J+K=74 \n" ); document.write( "J+3=3(K+3) \n" ); document.write( "J+3=3K+9 \n" ); document.write( "J=3K+9-3 \n" ); document.write( "J=3K+6 \n" ); document.write( "(3K+6)+K=74 \n" ); document.write( "4K=74-6 \n" ); document.write( "4K=68 \n" ); document.write( "X=68/4 \n" ); document.write( "K=17 AGE OF KEVIN NOW. \n" ); document.write( "J+17=74 \n" ); document.write( "J=74-17 \n" ); document.write( "J=57 AGE OF JOHN NOW. \n" ); document.write( "PROOF: \n" ); document.write( "57+3=3(17+3) \n" ); document.write( "60=3*20 \n" ); document.write( "60=60 \n" ); document.write( "############################# \n" ); document.write( "A+C=335 \n" ); document.write( "A=335-C \n" ); document.write( "10A+6C=2,590 \n" ); document.write( "10(335-C)+6C=2,590 \n" ); document.write( "3,350-10C+6C=2,590 \n" ); document.write( "-4C=2,590-3,350 \n" ); document.write( "-4C=-760 \n" ); document.write( "C=-760/-4 \n" ); document.write( "C=190 CHILDREN'S TICKETS WERE SOLD. \n" ); document.write( "A+190=335 \n" ); document.write( "A=335-190 \n" ); document.write( "A=145 ADULT TICKETS WERE SOLD. \n" ); document.write( "PROOF: \n" ); document.write( "10*145+190*6=2,590 \n" ); document.write( "1,450+1,140=2,590 \n" ); document.write( "2,590=2,590\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |