document.write( "Question 714247: One side of triangle is 2 times the shortest side. The third side is 16 feet more than the shortest side. The perimeter is 80. Find all three sides. \n" ); document.write( "
Algebra.Com's Answer #439151 by aliafzal14(13)\"\" \"About 
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ACCORDING TO THE GIVEN CONDITION
\n" ); document.write( "SHORTEST SIDE IS EQUAL TO THE = A= X
\n" ); document.write( "2ND SIDE IS EQUAL TO = B =2X
\n" ); document.write( "3RD SIDE IS EQUAL TO = C =16 + X\r
\n" ); document.write( "\n" ); document.write( "IN MATHEMATICALLY,
\n" ); document.write( " PERIMETER = A +B +C
\n" ); document.write( " PERIMETER = X + +2X + (16 +X)
\n" ); document.write( " 80 = 4X + 16
\n" ); document.write( "4X = 80-16
\n" ); document.write( "4X = 64
\n" ); document.write( " X = 64/4
\n" ); document.write( " X = 16
\n" ); document.write( "SHORTEST SIDE IS EQUAL TO THE = A= X = 16
\n" ); document.write( "2ND SIDE IS EQUAL TO = B =2X = 2*16 = 32
\n" ); document.write( "3RD SIDE IS EQUAL TO = C =16 + X = 16 + 16 = 32\r
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