document.write( "Question 62999: A bicyclist rode into the country for 5 h. In returning, her
\n" ); document.write( "speed was 5 mi/h faster and the trip took 4 h. What was her speed each way? \n" ); document.write( "
Algebra.Com's Answer #43913 by ankor@dixie-net.com(22740)\"\" \"About 
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A bicyclist rode into the country for 5 h. In returning, her
\n" ); document.write( "speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?
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\n" ); document.write( "Let s = initial speed, (s+5) = return speed
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\n" ); document.write( "We know the trip there, and the trip back are equal distances:
\n" ); document.write( " dist = time * speed
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\n" ); document.write( "Dist out = Dist back
\n" ); document.write( "5s = 4(s+5)
\n" ); document.write( "5s = 4s + 20
\n" ); document.write( "5s - 4s = 20
\n" ); document.write( "s = 20 mph is her intital speed:
\n" ); document.write( "Obviously, 25 mph is her return speed:
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\n" ); document.write( "Check using dist:
\n" ); document.write( "5(20) = 4(25)
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\n" ); document.write( "Make sense to you?\r
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