document.write( "Question 714868: it takes a plane traveling at a rate of 450 mph 25 minutes longer to travel a certain distance than it takes a second plane traveling at a rate of 500mph to travel the same distance. what is the distance.
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Algebra.Com's Answer #439113 by mananth(16946) $\"\"$ $\"About$

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let distance be y
\n" ); document.write( "time be x\r
\n" ); document.write( "\n" ); document.write( "distance = speed * time\r
\n" ); document.write( "\n" ); document.write( "y=450*(x-(25/60))\r
\n" ); document.write( "\n" ); document.write( "y=450*(x-5/12)
\n" ); document.write( "y= 450((12x-5)/12)\r
\n" ); document.write( "\n" ); document.write( "II plane\r
\n" ); document.write( "\n" ); document.write( "y= 500x\r
\n" ); document.write( "\n" ); document.write( "equate both equations\r
\n" ); document.write( "\n" ); document.write( "500x= 450(12x-5)/12\r
\n" ); document.write( "\n" ); document.write( "12*500x=450(12x-5)\r
\n" ); document.write( "\n" ); document.write( "6000x= 5400x-2250\r
\n" ); document.write( "\n" ); document.write( "600x=2250
\n" ); document.write( "x= 375 miles\r
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