document.write( "Question 714918: a womans age and her sons add up to 45 years, five years ago the woman was 6 times as old aas her son, how old was the woman when the boy was born \n" ); document.write( "
Algebra.Com's Answer #439111 by mananth(16946)\"\" \"About 
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woman's age=x
\n" ); document.write( "son's age = y\r
\n" ); document.write( "\n" ); document.write( "x+y = 45.............(1)\r
\n" ); document.write( "\n" ); document.write( "x-5 = 6(y-5)
\n" ); document.write( "x-5= 6y-30
\n" ); document.write( "x-6y=-25..............(2)\r
\n" ); document.write( "\n" ); document.write( "multiply equation (1) by 6
\n" ); document.write( "we get 6x+6y=270\r
\n" ); document.write( "\n" ); document.write( "add this to equation (2)\r
\n" ); document.write( "\n" ); document.write( "we get
\n" ); document.write( "7x= 245\r
\n" ); document.write( "\n" ); document.write( "x= 35\r
\n" ); document.write( "\n" ); document.write( "woman's age = 35\r
\n" ); document.write( "\n" ); document.write( "plug x
\n" ); document.write( "to get son's age
\n" ); document.write( "y=10\r
\n" ); document.write( "\n" ); document.write( "woman was 25 years when son was born\r
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