document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714924>Question 714924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose you are canoeing along a river with a steady current. your average speed upstream is 2.5 mi/h. on the return trip you paddle with the current, and your average speed is 4 mi/h. find the average speed of the current and your average speed if you were paddling in still water<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439108 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> speed of canoe in still water = x mph<BR>\n" );
document.write( "speed of current = y mph\r<BR>\n" );
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document.write( "Upstream speed = x-y =2.5<BR>\n" );
document.write( "downstream speed = x+y = 4\r<BR>\n" );
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document.write( "add both equations\r<BR>\n" );
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document.write( "2x=6.5<BR>\n" );
document.write( "x= 3.25\r<BR>\n" );
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document.write( "y= 3.25 -2.5 = 0.75\r<BR>\n" );
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document.write( " speed of canoe in still water = 3.25 mph<BR>\n" );
document.write( "speed of current = 0.75 mph\r<BR>\n" );
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