document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7996>Question 7996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cannot understand how to even start this problem.\r<BR>\n" );
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document.write( "Each car in a fleet of 24 rental cars is either red or blue.  There are 3 more blue cars than twice the number of red ones. How many red ones are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4391 by </B><A HREF=/tutors/aboutme.mpl?userid=CharStar><B>CharStar(110)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharStar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since you don't know how many red cars there are, Red is X.<BR>\n" );
document.write( "Since you do know how many blue cars there are, Blue is 2x+3 (twice red X plus 3) <BR>\n" );
document.write( "The total cars is 24. <BR>\n" );
document.write( "The equation is:<BR>\n" );
document.write( "Factor the equation <BR>\n" );
document.write( "Subtract 3 from both sides <BR>\n" );
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document.write( "Red x= 7<BR>\n" );
document.write( "Blue 2(7)+3= 17<BR>\n" );
document.write( "Total = 24 <BR>\n" );
document.write( "I hope that helps you<BR>\n" );
document.write( "CharStar </SPAN>\n" );
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