document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714944>Question 714944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve -12p=30p? I think you factor but how do you do that when you have only one or two numbers, because if im correct you subtract 30 from both sides to get 12p-30=0, but if you're trying to factor after that how do you do so?  Please provide a step by step on this for me. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439063 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -12P=30P<BR>\n" );
document.write( "-12P-30P=0<BR>\n" );
document.write( "(-12-30)P<BR>\n" );
document.write( "(-42)P=0<BR>\n" );
document.write( "-42P=0<BR>\n" );
document.write( "-42(1)=0<BR>\n" );
document.write( "-42.1=0<BR>\n" );
document.write( "-42=0====================RESULT<BR>\n" );
document.write( "P=0==================SOLUTION </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );