document.write( "Question 714769: Elliott street is 24ft wide when it ends at main street in brattleboro, vermont, a 40 ft long diagonal crosswalk allows pedestrians to cross main street to or from either corner of elliott street. determine the width of main street \n" ); document.write( "
Algebra.Com's Answer #439025 by ankor@dixie-net.com(22740)\"\" \"About 
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Elliott street is 24ft wide when it ends at main street in brattleboro, vermont, a 40 ft long diagonal crosswalk allows pedestrians to cross main street to or from either corner of elliott street. determine the width of main street
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\n" ); document.write( "Let m = the width of Main street
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\n" ); document.write( "draw this out marking the width of Elliot as 24 and the width of Main as m
\n" ); document.write( "The diagonal, the distance to opposite corners, is 40
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\n" ); document.write( "Find the angle (A) enclosed by the diagonal (40) and the width of Elliot (24)
\n" ); document.write( "Use the cosine for this
\n" ); document.write( "Cos(A) = \"24%2F40\"
\n" ); document.write( "A = 53.13 degrees
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\n" ); document.write( "Find the width of Main street using the sine of this angle
\n" ); document.write( "Sin(53.13) = \"m%2F40\"
\n" ); document.write( ".8 = \"m%2F40\"
\n" ); document.write( "m = .8 * 40
\n" ); document.write( "m = 32 ft is the width of main street
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