document.write( "Question 714769: Elliott street is 24ft wide when it ends at main street in brattleboro, vermont, a 40 ft long diagonal crosswalk allows pedestrians to cross main street to or from either corner of elliott street. determine the width of main street \n" ); document.write( "
Algebra.Com's Answer #439025 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Elliott street is 24ft wide when it ends at main street in brattleboro, vermont, a 40 ft long diagonal crosswalk allows pedestrians to cross main street to or from either corner of elliott street. determine the width of main street \n" ); document.write( ": \n" ); document.write( "Let m = the width of Main street \n" ); document.write( ": \n" ); document.write( "draw this out marking the width of Elliot as 24 and the width of Main as m \n" ); document.write( "The diagonal, the distance to opposite corners, is 40 \n" ); document.write( ": \n" ); document.write( "Find the angle (A) enclosed by the diagonal (40) and the width of Elliot (24) \n" ); document.write( "Use the cosine for this \n" ); document.write( "Cos(A) = \n" ); document.write( "A = 53.13 degrees \n" ); document.write( ": \n" ); document.write( "Find the width of Main street using the sine of this angle \n" ); document.write( "Sin(53.13) = \n" ); document.write( ".8 = \n" ); document.write( "m = .8 * 40 \n" ); document.write( "m = 32 ft is the width of main street \n" ); document.write( " |