document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714844>Question 714844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boy is three years older than his sister.the sum of their square ages is 369.how old are they </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #439023 by </B><A HREF=/tutors/aboutme.mpl?userid=JAE96><B>JAE96(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JAE96><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=439023\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 369= (x+3)+ (x)\r<BR>\n" );
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document.write( "369= (2x + 3)\r<BR>\n" );
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document.write( "369 - 3 = 2x +3 -3\r<BR>\n" );
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document.write( "366/2=2x/2\r<BR>\n" );
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document.write( "183 = x (The sister's age)\r<BR>\n" );
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document.write( "183+3 = 186(The Brother's age)\r<BR>\n" );
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document.write( "Plug it back in...\r<BR>\n" );
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document.write( "369 (186)+(183)\r<BR>\n" );
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document.write( "369=369\r<BR>\n" );
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