document.write( "Question 714760: I need to prove this identity
\n" ); document.write( "tan^2theta-sin^2theta = tan^2thetasin^2theta \n" ); document.write( "

Algebra.Com's Answer #438973 by josgarithmetic(39621) $\"\"$ $\"About$

You can put this solution on YOUR website!
On the left side we can say (sin^2)/(cos^2)-sin^2
\n" ); document.write( "=sin^2/cos^2-(sin^2*cos^2)/cos^2
\n" ); document.write( "=(sin^2 *(1-cos^2))/cos^2
\n" ); document.write( "= $\"%28%28sin%5E2%28theta%29%29%2F%28cos%5E2%28theta%29%29%29%281-cos%5E2%28theta%29%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To finish this, use $\"cos%5E2%28theta%29%2Bsin%5E2%28theta%29=1\"$ in the form of $\"1-cos%5E2%28theta%29=sin%5E2%28theta%29\"$ , and perform the substitution into that last step above. \n" ); document.write( "

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