document.write( "Question 714752: The measure of the first angle of a triangle is four times as large as the measure of the second angle. The thrid angle measures 15 less than twice the first angle. Find teh measures of the angle. I start out like this
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document.write( "Angle 1=a
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document.write( "Angle 2=b
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document.write( "Angle 3=c
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document.write( "a=4b
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document.write( "c=2a-15
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document.write( "Equation: 4b+b+2a-15=180.
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document.write( "Because there are two variables on this question im a little confused on how to make this work. \n" );
document.write( "
Algebra.Com's Answer #438972 by aliafzal14(13)![]() ![]() You can put this solution on YOUR website! as a=4b so b=a/4 \n" ); document.write( "so,\r \n" ); document.write( "\n" ); document.write( "4•a/4+a/4+2a-15=180 \r \n" ); document.write( "\n" ); document.write( "4•a/4+a/4+2a-15-180=0 \r \n" ); document.write( "\n" ); document.write( "5•a/4+2a-195=0 \n" ); document.write( "(5a)/4+(2a-195)=0 \n" ); document.write( "((5a)+4(2a-195))/4=0 \r \n" ); document.write( "\n" ); document.write( "Now we remove the brackets. \n" ); document.write( "(5a+8a-780)4=0 \n" ); document.write( " \n" ); document.write( "Arrange the terms. \n" ); document.write( "(13a-780)4=0 \n" ); document.write( "Let common 13 from the value \n" ); document.write( "(13(a-60))/4=0 \n" ); document.write( "(13/4)*(a-60)=0\r \n" ); document.write( "\n" ); document.write( "a-60=0 \n" ); document.write( "Let's move the constants to the right-hand side of the equality with the reverse sign. \n" ); document.write( "a=60 \n" ); document.write( "The final answer is: a=60 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first angle is =a =60 \n" ); document.write( "the second angle is =b =a/4=15 \n" ); document.write( "the third angle is = c = 2a -15 = 2(60) -15=120 -15=105 \n" ); document.write( " \n" ); document.write( " |