document.write( "Question 63057: 250 + 2k^3x
\n" ); document.write( "factor each polynomial. state prime if needed. \n" ); document.write( "

Algebra.Com's Answer #43896 by funmath(2933) $\"\"$ $\"About$

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250 + 2k^3x
\n" ); document.write( "factor the polynomial. state prime if needed.
\n" ); document.write( "2(125+k^3x) <---If the x is not part of the exponent, stop here.
\n" ); document.write( "If x is in the exponent, you have the sum of cubes that is factored by: $\"highlight%28a%5E3%2Bb%5E3=%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29%29\"$
\n" ); document.write( "125=5^3 (so a=5) and k^(3x)=(k^x)^3 (so b=k^x)
\n" ); document.write( " $\"2%285%2Bk%5Ex%29%285%5E2-5k%5Ex%2B%28k%5Ex%29%5E2%29\"$
\n" ); document.write( " $\"highlight%282%285%2Bk%5Ex%29%2825-5k%5Ex%2Bk%5E%282x%29%29%29\"$
\n" ); document.write( "Happy Calculating!!!!
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