document.write( "Question 714702: Nathan needs to make 30L of a 28% acid solution. He has 2 bottles, one containing 20% acid and the other containing 50% acid. What volume of each should he mix together to make the 28% acid solution? \n" ); document.write( "
Algebra.Com's Answer #438956 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
A very routine exercise. Let x = volume of the 20% acid to use and y = volume of the 50% acid to use.\r
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\n" ); document.write( "\n" ); document.write( "\"%2820x%2B50y%29%2F30=28\" AND \"x%2By=30\"\r
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\n" ); document.write( "\n" ); document.write( "The numbers were picked to make the arithmetic easier to do.
\n" ); document.write( "Managing the percentage equation,
\n" ); document.write( "(2x+5y)/3=28 just by removing factor of \"1=10%2F10\" from left side;
\n" ); document.write( "2x+5y=3*28
\n" ); document.write( "2x+5y=84\r
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\n" ); document.write( "\n" ); document.write( "System to solve is this:
\n" ); document.write( "\"2x%2B5y=84\"
\n" ); document.write( "\"x%2By=30\"\r
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\n" ); document.write( "\n" ); document.write( "Possible next step is
\n" ); document.write( "\"2x%2B5y-2%28x%2By%29=84-2%2A30\"
\n" ); document.write( "\"5y-2y=24\"
\n" ); document.write( "\"3y=24\"
\n" ); document.write( "\"highlight%28y=8%29\" liters for the 50% acid.\r
\n" ); document.write( "\n" ); document.write( "You can continue from here...\r
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\n" ); document.write( "\n" ); document.write( "Also notice, if 30 liters mixture is to result, as described, then this must be some huge bottle containing the x liters of the other acid!
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