document.write( "Question 714702: Nathan needs to make 30L of a 28% acid solution. He has 2 bottles, one containing 20% acid and the other containing 50% acid. What volume of each should he mix together to make the 28% acid solution? \n" ); document.write( "
Algebra.Com's Answer #438956 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! A very routine exercise. Let x = volume of the 20% acid to use and y = volume of the 50% acid to use.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The numbers were picked to make the arithmetic easier to do. \n" ); document.write( "Managing the percentage equation, \n" ); document.write( "(2x+5y)/3=28 just by removing factor of \n" ); document.write( "2x+5y=3*28 \n" ); document.write( "2x+5y=84\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "System to solve is this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Possible next step is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can continue from here...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also notice, if 30 liters mixture is to result, as described, then this must be some huge bottle containing the x liters of the other acid! \n" ); document.write( " |