document.write( "Question 714696: A stockbroker has money in three accounts. The interest rates on the three accounts are 6%, 8%, and 10%. If she has twice as much money invested at 8% as she has invested at 6%, three times as much at 10% as she has at 6%, and the total interest for the year is $208, how much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #438941 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
6% ---------x
\n" ); document.write( "8%---------2x
\n" ); document.write( "10%---------3x\r
\n" ); document.write( "\n" ); document.write( "6%*x+8%*2x+10%*3x=208\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 100\r
\n" ); document.write( "\n" ); document.write( "6x+16x+30x=20800\r
\n" ); document.write( "\n" ); document.write( "52x= 20800
\n" ); document.write( "x= 20800/52
\n" ); document.write( "x=400\r
\n" ); document.write( "\n" ); document.write( "you can calculate the others by plugging
\n" ); document.write( "
\n" );