document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714697>Question 714697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 70% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mix that is 60% antifreeze?  I tried doing .70(x)+.20(x+70)=.6 and came up with a negative answer of -14.88.  Please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438940 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -------------- 	percent	----------------	Amount									<BR>\n" );
document.write( "Amtifreeze I	20	----------------			70	gal						<BR>\n" );
document.write( "Antifreeze II	70	----------------			x	gal						<BR>\n" );
document.write( "Mixture	60	----------------	70	+	x	gal						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "20	*	70	+	70	x	=	60	(	70	+	x	)<BR>\n" );
document.write( "1400	+	70	x	=	4200	+	60	x				<BR>\n" );
document.write( "70	x		-60	x	=	-1400	+	4200				<BR>\n" );
document.write( "10	x	=	2800									<BR>\n" );
document.write( "/	10											<BR>\n" );
document.write( "x	=	280		gal	Antifreeze II							<BR>\n" );
document.write( "												<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
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