document.write( "Question 714677: How can $42,000 be invested, part at 4% annual simple interest and the remainder at 10% annual simple interest, so that the interest earned by the two accounts is equal at the end of the year? \n" ); document.write( "

Algebra.Com's Answer #438936 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = amount invested @ 4%
\n" ); document.write( " $\"+42000+-+x+\"$ = amount invested @ 10%
\n" ); document.write( "given:
\n" ); document.write( " $\"+.04x+=+.1%2A%28+42000+-+x+%29+\"$
\n" ); document.write( " $\"+.04x+=+4200+-+.1x+\"$
\n" ); document.write( " $\"+.14x+=+4200+\"$
\n" ); document.write( " $\"+x+=+30000+\"$
\n" ); document.write( " $\"+42000+-+30000+=+12000+\"$
\n" ); document.write( "$30,000 should be invested @ 4%
\n" ); document.write( "$12,000 should be invested @ 10%
\n" ); document.write( "check:
\n" ); document.write( " $\"+.04x+=+.1%2A%28+42000+-+x+%29+\"$
\n" ); document.write( " $\"+.04%2A30000+=+.1%2A12000+\"$
\n" ); document.write( " $\"+1200+=+1200+\"$
\n" ); document.write( "OK \n" ); document.write( "

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