document.write( "Question 714644: Use a calculator to evaluate the amortization formula.
\n" ); document.write( "For the values of the variables p, r and t( respectively) assume n =12.( round to the nearest cent)
\n" ); document.write( "$150,000; 6%; 25 yr.
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Algebra.Com's Answer #438925 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
using calculator http://www.vertex42.com/ExcelArticles/amortization-calculation.html, answer is: $\"+17891.55\"\r
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\n" ); document.write( "\n" ); document.write( "using formula:\r
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\n" ); document.write( "\n" ); document.write( "\"A=P%28r%281%2Br%29%5En%2F%28%281%2Br%29%5En-1%29%29\" \r
\n" ); document.write( "\n" ); document.write( "where
\n" ); document.write( " \"A\" => payment Amount per period
\n" ); document.write( " \"P=150+000\"=> initial Principal (loan amount)
\n" ); document.write( " \"r=0.06+\"= >interest rate per period
\n" ); document.write( " \"n+=12\"=> total number of payments or periods\r
\n" ); document.write( "\n" ); document.write( "we have\r
\n" ); document.write( "\n" ); document.write( "\"A=150000%280.06%281%2B0.06%29%5E12%2F%28%281%2B0.06%29%5E12-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=150000%280.06%281.06%29%5E12%2F%28%281.06%29%5E12-1%29%29\"......\"%281.06%29%5E12=2.012196471835550329409536\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=150000%280.06%2A2.012196471835550329409536%2F%282.012196471835550329409536-1%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=150000%280.12073178831013301976457216%2F1.012196471835550329409536%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=150000%280.119277%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=17891.55\"\r
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