document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714640>Question 714640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is four more than three times another number.  Find the numbers if the product is 175.\r<BR>\n" );
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document.write( "What I have tried:  3n(n+4)= 175 <BR>\n" );
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document.write( "                    3n^2+9-175 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438914 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is four more than three times another number.  Find the numbers if the product is 175.\r<BR>\n" );
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document.write( "What I have tried:  3n(n+4)= 175 **** How did you come up with that?<BR>\n" );
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document.write( "n = a number<BR>\n" );
document.write( "The other number is 4 plus 3 times the 1st number, = 3n+4<BR>\n" );
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document.write( "n*(3n+4) = 175<BR>\n" );
document.write( "Start from there.<BR>\n" );
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