document.write( "Question 714562: How do you solve this using substitution?
\n" ); document.write( "2x = y - 4
\n" ); document.write( "-3y = x - 5 \n" ); document.write( "

Algebra.Com's Answer #438873 by Dionysus10474(5) $\"\"$ $\"About$

You can put this solution on YOUR website!
2x = y - 4
\n" ); document.write( "-3y = x - 5\r
\n" ); document.write( "\n" ); document.write( "Make the factor of 1 variable equal to the factor of the same variable in the other equation.\r
\n" ); document.write( "\n" ); document.write( "I'll do both of them. First the x.\r
\n" ); document.write( "\n" ); document.write( "(2x)/2=(y - 4)/2
\n" ); document.write( "-3y - x = -5\r
\n" ); document.write( "\n" ); document.write( "x = 0.5y - 2
\n" ); document.write( "-3y - x = -5\r
\n" ); document.write( "\n" ); document.write( "Put the value of x from the first equation in the second equation.\r
\n" ); document.write( "\n" ); document.write( "-3y - (0.5y - 2) = -5
\n" ); document.write( "remember -1 * -2 = +2
\n" ); document.write( "-3y - 0.5y + 2 = -5
\n" ); document.write( "-3.5y + 2 = -5
\n" ); document.write( "-3.5y = -7
\n" ); document.write( "y = -7/-3.5
\n" ); document.write( "y = 2\r
\n" ); document.write( "\n" ); document.write( "put y in any of the original equations and you get your value of x\r
\n" ); document.write( "\n" ); document.write( "x = 0.5y - 2
\n" ); document.write( "so
\n" ); document.write( "2 = 0.5 y -2
\n" ); document.write( "4 = 0.5y
\n" ); document.write( "8 = y \n" ); document.write( "

\n" );