document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714517>Question 714517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system <BR>\n" );
document.write( "Y = -5x<BR>\n" );
document.write( "X +0.8*y = -7.2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438868 by </B><A HREF=/tutors/aboutme.mpl?userid=Dionysus10474><B>Dionysus10474(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Dionysus10474><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y        = -5x<BR>\n" );
document.write( "x + 0.8*y = -7.2\r<BR>\n" );
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document.write( "To solve this system you need to put both equations in one equation.\r<BR>\n" );
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document.write( "First equation: y =      -5x <BR>\n" );
document.write( "so 2*y =   2*(-5x)<BR>\n" );
document.write( "and therefore 0.8*y = 0.8*(-5x) <BR>\n" );
document.write( "which we have in the second equation, so we can put 0.8*y in the second equation.\r<BR>\n" );
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document.write( "x + (0.8*(-5x)) = -7.2<BR>\n" );
document.write( "x +       -4x   = -7.2<BR>\n" );
document.write( "          -3x   = -7.2<BR>\n" );
document.write( "            x   = -7.2/-3<BR>\n" );
document.write( "            x   = 2.4\r<BR>\n" );
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document.write( "Put x in the first equation and you get the value of y.\r<BR>\n" );
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document.write( "y = -5x<BR>\n" );
document.write( "y = -5*2.4<BR>\n" );
document.write( "y = -12 </SPAN>\n" );
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