document.write( "Question 714400: Find the center, radius, and intercepts of the circle with the given equation x^2+y^2+10y-24=0 \n" ); document.write( "
Algebra.Com's Answer #438799 by josgarithmetic(39617)\"\" \"About 
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The intercepts will be when x=0 and you solve for y, and when y=0 and you solve for x. Both situations will give you quadratic equation in one variable. \r
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\n" ); document.write( "\n" ); document.write( "\"0%2A0%2By%5E2%2B10y-24=0\" becomes \"y%5E2%2B10y-24=0\" for whe x=0. Easily factorable to \"%28y-2%29%28y%2B12%29=0\", so intercepts will be at y=2 and y=-12. So see how that works? You can do the same for finding the intercepts when y=0.\r
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\n" ); document.write( "\n" ); document.write( "Finding radius and center need a different equation form. Put the equation into standard form by Completing the square. Do this for BOTH variables.\r
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\n" ); document.write( "\n" ); document.write( "Here's getting the process started.
\n" ); document.write( "x^2+y^2+10y-24=0
\n" ); document.write( "x is already in good shape. No need to complete the square for x. y needs some work.
\n" ); document.write( "The square term to add and subtract is \"%2810%2F2%29%5E2=25\".
\n" ); document.write( "\"%28y%5E2%2B10y%2B25%29-25=%28y%2B5%29%5E2-25\". We now must include that in the original equation:\r
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\n" ); document.write( "\n" ); document.write( "Putting that result into the original equation, we obtain:
\n" ); document.write( "\"x%5E2%2B+%28y%2B5%29%5E2-25+-24+=0\"
\n" ); document.write( "\"highlight%28x%5E2%2B%28y%2B5%29%5E2=49%29\"
\n" ); document.write( "OR
\n" ); document.write( "\"highlight%28x%5E2%2B%28y%2B5%29%5E2=7%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Center is at (0,-5) and radius is 7.
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