document.write( "Question 714383: what is the value of x when 6x + 12 > 0? \n" ); document.write( "
Algebra.Com's Answer #438789 by harrysgirl143(11)![]() ![]() ![]() You can put this solution on YOUR website! 6x+12 *greaterthan* 0 \n" ); document.write( "6x *greater than* -12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is greater than -2 \n" ); document.write( " |