document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714344>Question 714344</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My question is: Use substitution to solve this- y=2x-5 & 3y-x=5<BR>\n" );
document.write( "i tried adding them together then dividing it by 2, but it came out wrong. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438778 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3y-x=5\r<BR>\n" );
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document.write( "3(2x-5)-x=5 ... plug in y = 2x-5 (ie replace y with 2x-5, we can do this because y and 2x-5 are the same)\r<BR>\n" );
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document.write( "6x - 15 - x  = 5\r<BR>\n" );
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document.write( "5x - 15 = 5\r<BR>\n" );
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document.write( "I'll let you finish. You need to solve that equation for x. Once you have x, you can use that value of x, along with y = 2x - 5, to find y. </SPAN>\n" );
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