document.write( "Question 714223: How much distilled water must be mixed with alcohol 70% to prepare 5 L of alcohol 40%? \n" ); document.write( "
Algebra.Com's Answer #438737 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+w+\" = liters of distilled water to be used
\n" ); document.write( "Let \"+x+\" = liters of 70% alcohol to be used
\n" ); document.write( "\"+.7x+\" = liters of alcohol in 70% solution
\n" ); document.write( "------------
\n" ); document.write( "I end up with 5 liters, so
\n" ); document.write( "(1) \"+w+%2B+x+=+5+\"
\n" ); document.write( "and also,
\n" ); document.write( "(2) \"++.7x+%2F+5+=+.4+\"
\n" ); document.write( "----------------
\n" ); document.write( "(2) \"+.7x+=+2+\"
\n" ); document.write( "(2) \"+x+=+2.8571+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+w+%2B+x+=+5+\"
\n" ); document.write( "(1) \"+w+%2B+2.8571+=+5+\"
\n" ); document.write( "(1) \"+w+=+2.1429+\"
\n" ); document.write( "2.1429 liters of water must be used\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );