document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714238>Question 714238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I am working with functions just substituting and solving problems. The given is f(x)=5x^2+4x-3 and what I am trying to solve is f(x+1) put into the equation. I understand that to substitute the problem would be f(x+1)=5(x+1)^2+4(x+1)-3 I am just unsure of how to solve. If you could help that would be great. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438736 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438736\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=5x^2+4x-3 \r<BR>\n" );
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document.write( "f(x+1)=5(x+1)^2+4(x+1)-3 ... so far, so good\r<BR>\n" );
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document.write( "Now you expand, distribute, and combine like terms to simplify\r<BR>\n" );
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document.write( "f(x+1)=5(x+1)(x+1)+4(x+1)-3\r<BR>\n" );
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document.write( "f(x+1)=5(x^2+2x+1)+4(x+1)-3\r<BR>\n" );
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document.write( "f(x+1)=5x^2+10x+5+4x+4-3\r<BR>\n" );
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document.write( "f(x+1)=5x^2+14x+6\r<BR>\n" );
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document.write( "So the answer is f(x+1)=5x^2+14x+6 </SPAN>\n" );
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