document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=63063>Question 63063</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following systems by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.<BR>\n" );
document.write( "2x + 3y = 1<BR>\n" );
document.write( "5x + 3y = 16<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43869 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Equation 1 : 2x + 3y = 1<BR>\n" );
document.write( "Equation 2 : 5x + 3y = 16<BR>\n" );
document.write( "Subtract equation 1 from equation 2 to obtain<BR>\n" );
document.write( "3x=15 Divide both sides by 5 to get<BR>\n" );
document.write( "x = 5<BR>\n" );
document.write( "Substitute x=5 into the first equation<BR>\n" );
document.write( "2*5 + 3y = 1<BR>\n" );
document.write( "10 + 3y = 1 Subtract 10 from each side of the equation<BR>\n" );
document.write( "10 + 3y - 10 = 1 - 10<BR>\n" );
document.write( "3y = -9 Divide each side by 3<BR>\n" );
document.write( "y = -3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );