document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=714083>Question 714083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill leaves his house for Makayla's house riding his bicycle at 8 miles per hour. At the same time, Makayla leaves her house heading toward Bill's house walking a 3 miles per hour. <BR>\n" );
document.write( "Write a system of equations to represent the distance, d, each is from Makayla's house in hours, h. They live 8.25 miles apart. <BR>\n" );
document.write( "Solve the system to determine how long they travel before meeting.\r<BR>\n" );
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document.write( "Have tried 4 times...cannot figure out how to set up the equation...I can sole it once it is set up.\r<BR>\n" );
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document.write( "I tried:\r<BR>\n" );
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document.write( "8.25=d-8h   8.25=d-3y\r<BR>\n" );
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document.write( "8.25=d-8h    8.25=d-3h\r<BR>\n" );
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document.write( "x=8.25d-3h    x=8.25d-3h\r<BR>\n" );
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document.write( "8d-h=8.25    3d-h=8.25<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438677 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bill leaves his house for Makayla's house riding his bicycle at 8 miles per hour. At the same time, Makayla leaves her house heading toward Bill's house walking a 3 miles per hour. <BR>\n" );
document.write( "Write a system of equations to represent the distance, d, each is from Makayla's house in hours, h. They live 8.25 miles apart. <BR>\n" );
document.write( "Solve the system to determine how long they travel before meeting.<BR>\n" );
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document.write( "There are 2 distances --> 2 equations<BR>\n" );
document.write( "for Bill:<BR>\n" );
document.write( "d = 8.25 - 8t, d in miles, t in hours<BR>\n" );
document.write( "For Makayla:<BR>\n" );
document.write( "d = 0 + 3t = 3t<BR>\n" );
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document.write( "They meet when they're the same distance from the house.<BR>\n" );
document.write( "8.25 - 8t = 3t<BR>\n" );
document.write( "11t = 8.25<BR>\n" );
document.write( "t = 0.75 hours<BR>\n" );
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