document.write( "Question 714044: the perimeter of a garden is 66 m and its area is 270 square meter. find the dimension of the garden..\r
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\n" ); document.write( "\n" ); document.write( "pleaseee help me:)))
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Algebra.Com's Answer #438649 by Simnepi(216)\"\" \"About 
You can put this solution on YOUR website!
If you draw a rectangle, (go on, draw one!) and label the lengths as l and the widths as w, then the perimeter is
\n" ); document.write( "l+w+l+w or, simplifying this we get 2l+2w removing the common factor gives
\n" ); document.write( "2(l+w) this = 66m
\n" ); document.write( "dividing both sides by 2 gives
\n" ); document.write( "l + w = 33
\n" ); document.write( "rearranging this gives us
\n" ); document.write( "l = 33 - w let's call this equation (1)
\n" ); document.write( "Now.....
\n" ); document.write( "the area of a rectangle is l*w, this is = 270
\n" ); document.write( "i.e.
\n" ); document.write( "l * w = 270 let's call this equation (2)
\n" ); document.write( "using equation (1) in equation (2) gives
\n" ); document.write( "(33-w) * w = 270
\n" ); document.write( "multiplying out the bracket gives
\n" ); document.write( "\"33w+-+w%5E2+=+270\"
\n" ); document.write( "rearranging this equation gives
\n" ); document.write( "\"w%5E2+-+33w+%2B+270+=+0\"
\n" ); document.write( "using the formula for quadratics
\n" ); document.write( "\"w+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "gives
\n" ); document.write( "w = 18 or 15
\n" ); document.write( "since the width must be smaller than the length
\n" ); document.write( "this gives the length as 18 m and the width = 15 m
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