document.write( "Question 714005: john needs to mix 10% saline solution with 30% saline to create 200 milliliters of 18% solution. How much milliliters must john use? \n" ); document.write( "
Algebra.Com's Answer #438636 by josgarithmetic(39617)\"\" \"About 
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x and y for volume to use of the 10% saline and for the 30% saline.\r
\n" ); document.write( "\n" ); document.write( "\"%2810x%2B30y%29%2F200=18\" AND \"x%2By=200\".\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%2B3y%29%2F20=18\"
\n" ); document.write( "\"x%2B3y=20%2A18\"
\n" ); document.write( "\"x%2B3y=360\"\r
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\n" ); document.write( "\n" ); document.write( "Solve this system for x and y:
\n" ); document.write( "\"highlight%28x%2B3y=360%29\"
\n" ); document.write( "\"highlight%28x%2By=200%29\"\r
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\n" ); document.write( "\n" ); document.write( "The easiest way to continue is subtract the second equation from the first equation (of the system, of course) to very easily obtain a value for y, the volume to use of the 30% saline.
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