document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=713867>Question 713867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this: \r<BR>\n" );
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document.write( "y = 2x - 2<BR>\n" );
document.write( "3x + 4y = 3\r<BR>\n" );
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document.write( "thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438598 by </B><A HREF=/tutors/aboutme.mpl?userid=BGutridge><B>BGutridge(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=BGutridge><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since one equation is already solved for \"y\", plug that expression in for \"y\" in the other equation   3x+4(2x-2)=3.  Then simplify, leaving:<BR>\n" );
document.write( "3x+8x-8=3<BR>\n" );
document.write( "11x=11<BR>\n" );
document.write( "x=1<BR>\n" );
document.write( "Plugging x back into the other equation, you get y=2(1)-2, or y=0, so the complete solution is (1,0) </SPAN>\n" );
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