document.write( "Question 713821: Please help me solve this question
\n" ); document.write( "-x+y=1
\n" ); document.write( "2x+y=-2
\n" ); document.write( "Solve using substitution method \n" ); document.write( "

Algebra.Com's Answer #438580 by BGutridge(15) $\"\"$ $\"About$

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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
\n" ); document.write( " $\"+system%28+%0D%0A++++-1%5Cx+%2B+1%5Cy+=+1%2C%0D%0A++++2%5Cx+%2B+1%5Cy+=+-2+%29%0D%0A++\"$ We'll use substitution. After moving 1*y to the right, we get:
\n" ); document.write( " $\"-1%2Ax+=+1+-+1%2Ay\"$ , or $\"x+=+1%2F-1+-+1%2Ay%2F-1\"$ . Substitute that
\n" ); document.write( " into another equation:
\n" ); document.write( " $\"2%2A%281%2F-1+-+1%2Ay%2F-1%29+%2B+1%5Cy+=+-2\"$ and simplify: So, we know that y=0. Since $\"x+=+1%2F-1+-+1%2Ay%2F-1\"$ , x=-1.
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\n" ); document.write( " Answer: $\"system%28+x=-1%2C+y=0+%29\"$ .
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