document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=713824>Question 713824</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -x+y=1<BR>\n" );
document.write( "2x+y=-2<BR>\n" );
document.write( "Solve using substitution method and elimination method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438577 by </B><A HREF=/tutors/aboutme.mpl?userid=iamverybadinmath><B>iamverybadinmath(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=iamverybadinmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=iamverybadinmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a pretty simple problem if you know how to substitute problems.  <BR>\n" );
document.write( "    The answer to this problem is:  <BR>\n" );
document.write( "                               x=-1<BR>\n" );
document.write( "                               y=0<BR>\n" );
document.write( "Here's the work:<BR>\n" );
document.write( "             2x+y-(-x)-y=-2-1<BR>\n" );
document.write( "                2x+x+y-y=-3<BR>\n" );
document.write( "                        3x=-3<BR>\n" );
document.write( "                          x=-1<BR>\n" );
document.write( "Then you substitute x into equation 1:<BR>\n" );
document.write( "             -(-1)+y=1<BR>\n" );
document.write( "                     y=1-(-(-1))<BR>\n" );
document.write( "                     y=1-1<BR>\n" );
document.write( "                     y=0<BR>\n" );
document.write( "I hope you understand my work and explanation, you can email me if you have any more questions! Enjoy!     ;) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );