document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=713234>Question 713234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill invests in a plan that has an interest rate of 2%. He invests two times as much in a plan that has an interest rate of 3%. If the total interest from the investments is $ 336 after one year how much was invested in each plan? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438332 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bill invests in a plan that has an interest rate of 2%. He invests two times as much in a plan that has an interest rate of 3%. If the total interest from the investments is $ 336 after one year how much was invested in each plan?<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "interest + interest = interest<BR>\n" );
document.write( "0.02x + 0.03(2x) = 336<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "2x + 6x = 33600<BR>\n" );
document.write( "8x = 33600<BR>\n" );
document.write( "x = $4200 (amt. invested in the 2% plan)<BR>\n" );
document.write( "2x = $8400 (amt. invested in the 3% plan)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );