document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=713125>Question 713125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An inverted conical tank of radius 3 meters and altitude of 9 meters contains water to a depth of 3 meters. How much water must be added into the tank such that the depth of water will be doubled? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438301 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The tank volume is radius squared times pi, times height, divided by 3.<BR>\n" );
document.write( "In cubic meters, that is 3 squared, times pi, times 9, divided by 3,<BR>\n" );
document.write( "which calculates to 27pi<BR>\n" );
document.write( "The water in the tank occupies a similar cone, <BR>\n" );
document.write( "with all dimensions proportionally smaller by a factor of 3.<BR>\n" );
document.write( "That volume is smaller by a factor of 3 cubed, or 27.<BR>\n" );
document.write( "So the volume of water in the tank is pi cubic meters.<BR>\n" );
document.write( "The volume when the water is twice as deep is the volume of a similar cone,<BR>\n" );
document.write( "2 times as large in all dimensions.<BR>\n" );
document.write( "That makes the volume larger by a factor of 2 cubed, or 8.<BR>\n" );
document.write( "The amount of water that needs to be added is 7 times what is in the tank,<BR>\n" );
document.write( "or 7pi cubic meters.<BR>\n" );
document.write( "That is about 22 cubic meters, which is 22,000 liters. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );