document.write( "Question 713064: a cylindrical standpipe is contain 343000 gal. of water. If its height is to be twice it diameter, what must be its dimension? \n" ); document.write( "
Algebra.Com's Answer #438294 by ankor@dixie-net.com(22740)\"\" \"About 
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cylindrical standpipe is contain 343000 gal. of water. If its height is to be twice it diameter, what must be its dimension?
\n" ); document.write( ":
\n" ); document.write( "the vol of a cylinder: \"V+=+pi%2Ar%5E2%2Ah\"
\n" ); document.write( "h = twice the diameter which is 4 times the radius
\n" ); document.write( "therefore
\n" ); document.write( "\"pi%2Ar%5E2%2A4r\" = 342000
\n" ); document.write( "divide both sides by 4pi, resulting in
\n" ); document.write( "\"r%5E3\" = 27295
\n" ); document.write( "find the cube root
\n" ); document.write( "r = 30.11
\n" ); document.write( ":
\n" ); document.write( "Diameter = 60.22
\n" ); document.write( "height: = 120.44
\n" ); document.write( ":
\n" ); document.write( "Check
\n" ); document.write( "\"pi%2A30.11%5E2%2A120.44\" = 343038 ~ 343000
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